【领扣leetcode数据库】180. 连续出现的数字

题目描述

编写一个 SQL 查询,查找所有至少连续出现三次的数字。

+----+-----+
| Id | Num |
+----+-----+
| 1  |  1  |
| 2  |  1  |
| 3  |  1  |
| 4  |  2  |
| 5  |  1  |
| 6  |  2  |
| 7  |  2  |
+----+-----+

例如,给定上面的 Logs 表, 1 是唯一连续出现至少三次的数字。

+-----------------+
| ConsecutiveNums |
+-----------------+
| 1               |
+-----------------+

代码

/* Write your T-SQL query statement below */
selectdistinct num as consecutivenums
from(select a.num as num,case when a.num=b.num and b.num = c.num then 1else 0end as is_consecutivefrom logs aleft join logs bon a.id+1 = b.idleft join logs con a.id+2 = c.idwhere c.id is not null)t
where is_consecutive=1

##问题:如果需要找连续十次出现的数字,那需要十张表相连,不太科学,可以尝试使用用户变量

# Write your MySQL query statement below
select distinct num as consecutivenums
from (select num,case when @prev = num then @count := @count + 1when (@prev := num) is not null then @count := 1end as cntfrom logs, (select @prev := null,@count := null) as t) temp
where temp.cnt >= 3